In a screw gauge, there are 100 divisions on the circular scale and the main scale moves by 0.5 mm on a complete rotation of the circular scale. The zero of circular scale lies 6 divisions below the line of graduation when two studs are brought in contact with each other. When a wire is placed between the studs, 4 linear scale divisions are clearly visible while 46 th division the circular scale coincide with the reference line. The diameter of the wire is _____ x 10 -2 mm.
Text Solution
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(22)
Least count = 
Least count = 5 x 10 -3 mm
Positive Error = MSR + CSR (LC)
= 0 mm + 6 (5 x 10 -3 mm)
Reading of Diameter = MSR + CSR (LC)
Positive zero error
= 4 x 0.5 mm + (46(5 x 10 -3 )) - 6(5 x 10 -3 ) mm
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